Problem Statement:
Given a sequence of brackets, validate if the sequence is valid.
Solution:
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We all must have solved this problem during college as common application of stack for solving mathematical expressions. Below is the implementation to validate given sequence of brackets.
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Happy Coding !! :)
Given a sequence of brackets, validate if the sequence is valid.
Solution:
Run Source Code
We all must have solved this problem during college as common application of stack for solving mathematical expressions. Below is the implementation to validate given sequence of brackets.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 | import java.util.HashMap; import java.util.Map; import java.util.Stack; /** * Given an sequence of brackets , confirm if sequence is valid * @author PRATEEK */ public class ValidateBrackets { private static Map<Character,Character> hash = new HashMap<>(); static { hash.put('{','}'); hash.put('[',']'); hash.put('(',')'); } /** * Sub-routine to validate the sequence of brackets * @param s * @return */ public static boolean validate(String s){ char[] arr = s.toCharArray(); Stack<Character> stack = new Stack<>(); for(Character c:arr) { switch (c) { case '[': case '{': case '(': stack.push(c); break; case ']': case '}': case ')': { if(hash.values().contains(c)) { if(!stack.isEmpty() && hash.get(stack.peek())==c) stack.pop(); else if(stack.isEmpty()) return false; } } break; default: break; } } return stack.isEmpty(); } public static void main(String[] args) { String s= "{()}[]"; boolean isValid = validate(s); System.out.println("input: "+s); System.out.println("output: " +isValid); } } |
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Please comment and post your suggestions.
Happy Coding !! :)
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