**Puzzle Problem : (Hand Shake Problem)**

Ten people (five couples) go to a party and start shaking hands.

You don't shake your spouse's hand or (of course) your own.

Give number of handshakes that happened at the party.

Answer:

There are totally 40 handshakes....

First couple handshake with other is 8+8 = 16

Second couple handshake with other except first couple..becuase we already add their handshakes.

so i.e. 6+6 = 12

Third couple handshakes is 4+4 = 8 (minus the first two couples handshake)

Fourth couple handshakes is 2+2 = 4 (minus the first three couples handshake)

Last couple handshakes is 0+0 = 0 (minus the first four couples handshake)

so total 16+12+8+4 = 40

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